SOLVED: What is the major product of the reaction between ethylbenzene and mole of bromine water (Brz) in the presence of UV light? Br CH3 CHa
![CH3 - CH3 |CH - CH2 - CH3 + Br2 []hv P (Major product) (on monobromination) The product P is :](https://dwes9vv9u0550.cloudfront.net/images/2304059/7d46bad0-ae7d-495b-b4d8-235c2060833c.jpg "CH3 - CH3 |CH - CH2 - CH3 + Br2 []hv P (Major product) (on monobromination) The product P is :")
CH3 - CH3 |CH - CH2 - CH3 + Br2 []hv P (Major product) (on monobromination) The product P is :
SOLVED: Free radical bromination of an alkane with a halogen with UV light as catalyst (for example, pentane with bromine) has three steps: Br2 Br UV HBr A: initiation, propagation, termination B:
Please show me mechanism with reason for the addition of Br2 in cyclohexene in the presence of heat and UV - Chemistry - Haloalkanes and Haloarenes - 9553865 | Meritnation.com
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![CH3 - CH3 []Br2/hvA []LiAlH4B []Br2/hvC []Na/etherD The compound D is:](https://dwes9vv9u0550.cloudfront.net/images/3608069/07d40cff-181a-4ac8-bf10-20d0b19e64e0.jpg "CH3 - CH3 []Br2/hvA []LiAlH4B []Br2/hvC []Na/etherD The compound D is:")
CH3 - CH3 []Br2/hvA []LiAlH4B []Br2/hvC []Na/etherD The compound D is:
2 - Bromo - 3 - phenylpropane can be synthesized by:
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When a chemist reacts 2-methylbutane with Br2 and UV light, the major product will be 2-bromo-3-methylbutane. a) true b) false | Homework.Study.com
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In presence of U.V. light bromination of benzene produces:A.${C_6}{H_5}Br$B.${C_6}{H_6}B{r_6}$C.o p DibromobenzeneD.No reaction will be take place
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When you react 2-methyl butane with Br_2 and UV light, the major product will be 2-Bromo-2-methyl butane. Is the statement true or false? | Homework.Study.com
